This whole discussion is about AdobeRGB vs sRGB. If your opinion is the last video is misleading, unprofessional, etc. then this video will have as only the information that was gleaned from the tests. Camera to print, staying in their respective color spaces, and put out for the public to vote. Will they say, "I can't really tell" or will they say, "AdobeRGB is much better"?
I still haven't heard anybody going on record saying that the AdobeRGB is going to win. Just a bunch of snipes off topic.
Gary
I learned Color Management the hard way.
I photographed a wedding in which the bride's mother wore a deep cyan dress. I shot RAW.
When I printed the image file on my properly profiled inkjet printer I could not (initially) match the screen to my print - on the color of that dress alone.
I assumed the printer was wrong. It wasn't. The monitor I was using at the time, whose gamut was closer to sRGB than to the printer's much wider gamut, was clipping the cyans to blue.
I have since invested in a wide gamut monitor and the situation is now very sensible.
But this is a very instructive image.
If I leave it in ProPhoto, or convert to AdobeRGB, and then print on my inkjet (converting to the inkjet profile on the way), I get a true representation of the bride's mother's dress. Deep cyan. She is happy.
If I convert to sRGB and print, I get a blue dress. She is not happy. The color is wrong.
Why would I ever convert to sRGB? (1) to put the image onto the web even though I know that colour is wrong and (2) to demonstrate to students the inadequacy of restricting captured colour to the sRGB color space.
If, in your experiment, each image is finally converted to a good colour profile for your print, and if the color gamut of your inkjet is as wide as mine, I predict the the pictures of all but one of the squares on the colour checker will look exactly the same whether you shot JPEG sRGB or JPEG aRGB. The cyan square will be cyan in the aRGB workflow, and blue in the sRGB. Will it be better? What does that mean? The representation in the aRGB workflow will be more accurate.
Just my 2¢
Tim