If you don't know all this, why are you taking on this job?
You can always learn from a job.
You don't need a RIP per se IF you're dealing with rasterized data. That's what a RIP really does; rasterize postscript or vector data. What you may need is a 3rd party print driver IF again, you're going to be dealing with CMYK. The native Quickdraw/GDI drivers from Epson and Canon as an example, do not deal with CMYK correctly. You can stick to RGB for such proofing in some cases and avoid another driver with good output profiles; one for the proofer (Canon/Epson) and one that defines the process you are proofing towards. A press? A contract proof?
I'm not sure if he needs a RIP or not so it is still under consideration.
I'll know a bit more after the meeting by tomorrow.
My situation is a bit complex since we are dealing with differnt parties. An actual company who knows nothing at all, a photo retoucher who knows a bit color managment, a print service provider who seems to know nothing about color managment but a close loop one.
I am actually hired by the retoucher who is complaining the printer always edit his final files because they cannot reproduce the right color for the company.
What I was thinking is to help the company to setup a printer, in-house, for their designers. Once the photo retoucher send them a new file, after their design within AI or Indesign, export it to a rasterized file, print it out from photoshop with CMYK simulation aka hard proofing. Send the hard proof to the printer and tell them to shut up and match the proof. A legal contract proof might be too much for them, not about money, but how you know what I mean. Sometimes client doesn't want too much.
I'm living in China and this is what we are dealing with everyday. Back in the day when I was working in a publishing company, I had to go down to the printer, look at every single round of fresh prints from the offset for 20 hours and tell them more M less C.....bla bla bla......
So, Mr. Rodney, am I using the correct setting for the hardproof function in Photoshop?
Thanks
Aaron