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My husband thinks it looks better at 96dpi as opposed to 300dpi but I don't really notice a difference.
Though this has been covered, I'm not sure it's yet clear so let me add my .02 ....
The "only" thing which is important is the file size in pixels (horizontal by vertical). Print density has absolutely nothing to do with anything and is only important to the print device. Display density (how many pixels per inch) depends on your graphics card, settings and the size you wish to see the image on display. So things like 96 ppi (not dpi) and 300 dpi don't even belong in the same frame of reference.
A digital camera captures an image at full resolution, whatever that may be depending on the sensor itself. At a given capture resolution (file dimension) of so many pixels wide by so many pixels tall, there is but a single size which can be printed at a fixed "print density" of so many "dpi". If the print device wants 300 dots per inch, then you divide the horizontal number of pixels and the vertical number of pixels by 300 and that gives you the one and only dimensions the file can be printed at for 300 dpi. Let's say we have a 2 megapixel capture which is 1600 pixels by 1200 pixels (horizontal by vertical). Then dividing 1600 pixels across by 300 dots per inch desired print density yields 5.33 inches wide. Dividing 1200 pixels (the height) by 300 dots per inch yields 4.00 inches. So the "only" size print possible at 300 dpi for this file is 5.33 inches by 4.00 inches.
But you don't want a 5.33 by 4.00 inch print you want an 8x10. To get this you then must "add" pixels to get to an appropriate matrix size to yield an 8x10 print. Multiply 10 by 300 and you get 3000 pixels. Multiply 8 by 300 and you get 2400. So the "interpolation" algorithm must increase the file size to 3000 by 2400 pixels to get an 8x10 print at 300 dpi.
You'll notice this has nothing to do with the 72 dpi (actually ppi) display pixel density or the 96 ppi display density. If you display the 1600 pixels at 96 pixels per inch on the screen, the image will be 16.66 inches in width (1600/96=16.66). It will be 12.5 inches tall (1200/96=12.5). These number simply represent how many pixels your display card shows within one inch of screen space. Notice that nothing has been "done" to the file, but if you "ask" the computer to display this file within a prescribed space which is less than 16.66 inches by 12.5 inches and keep the 96 dots or "pixels" per inch density, then the computer must downsample the file matrix to an appropriate display size by temprorarily "removing" pixels.
You want to send the full sized file to the printer. Don't interpolate or downsample it, let them take care of that on their end when they print. Printers (the machine, not the person) have their own print drivers which RIP (provide interpolation or downsampling) the file appropriately for the desired print size.
Just have the photographer give you the images he took, let your husband make any necessary improvements then save them at the full resolution size and don't worry about the 72dpi or 96dpi or 300dip - it's not important at this stage.
Best regards,
Lin[/font]