> If the image you included is that case, then I'd suspect that the 7 pieces of white tape have completely thrown the recognition off.
Yes but only because scanin placed the frames on them, outside the actual target.
It's setup to recognize rectangular patches, and bits of white tape look very much like high contrast rectangular patches. It doesn't have an ability to recognize general objects like frames (it's not A.I.), but will tend to ignore anything that doesn't look like rectangular patches.
With the target image downscaled to 1/2 instead of 1/4, the diag.tif looked different and worked. It looks to me like scanin wants a certain fixed minimum size for the target image.
It's size independent. Too low a resolution and it will fail (won't be able to detect edges, and/or not enough pixels in a patch), too high also risks not detecting edges and noise being detected as edges, but there is a very wide margin in between.
But apart from that, my understanding is correct, or at least in accordance with yours?
Adding such a patch fundamentally defeats the purpose of characterizing the device. If you already know/assume that zero maps to zero, why are you measuring it ? That's not to say it's always wrong, but be aware of what it implies.
If so, I don't understand how the two following statements relate to each other:
> Note that the black point tag is simply annotation - it has no effect on the actual profile itself.
> It will have a weighting in the matrix fit of the sample points.
If you edit the profile and change the black point tag, the way the profile says the device behaves doesn't change.
If you add a test point saying that perfect black measures as RGB=0 by the device, then this will have an effect on the cLUT/matrix/shaper model that colprof will create (except the special case of a matrix only profile, in which case there is no point in adding such a patch value).
I imagine the latter translates to that the 0 black point lifts the shadows? (if it does anything at all).
Its effect will depend on how the device actually measures or is extrapolated to measure perfect black. It may lift or reduce or make no change to the shadows.