If one attempts to do horizontal multi-shot images with the camera tilted down/up, the problem becomes placing the nodal point at the vertical axis of rotation. We all experimentally find the nodal point for out seutps, but that is with the whole thing horizontally leveled. I am personally dealing with this issue and have seen numerous posts on various boards so I thought I would post my solution. bjanes on this board recommended the following setup as in inexpensive way to do it.
The one issue with this setup is that as the camera is tilted back and forth the nodal point will shift away from the axis of rotation. This is relatively easy to solve with a little math. Assuming you already determined the nodal point for the lens/camera combination when horizontally level and we designate the tilt of the head from 90° (forward) to 0° (Vertical) to -90° (backward) then given the image below(
note: my tilt head has degree markings on it...not sure how accurate):
A = Nodal Point
B = Point where horizontal line through nodal point meets sensor plane
C = Point of rotation of the tilt head
T = Tilt of head 90° to -90° (Pi/2 to -Pi/2 Radians)
x = Horizontal normal nodal distance
y = Vertical distance from tilt head axis of rotation to nodal point axis
z = Hypotenuse of our right triangle
We can calculate theta = arctan(y/x)
When we tilt the head we are increasing or decreasing theta by adding or subtracting so
Theta' = Theta - T
Now the new nodal distance x' = cos(Theta') * SQRT(x^2 + y^2) =
cos(arctan(y/x) - T)* SQRT(x^2 + y^2)Depending on your x and y distances, you will notice different rates of shift tilting forward and back. I would do this ahead of time just like you did with finding your nodal points for your lenses. I made a spreadsheet and then keep a cheat sheet for a few angles of tilt. You can check your work by setting Tilt = 90°, -90° and Theta which should result in your answers being the value of y, -y and the length of the hypotenuse of the original triangle respectively. This makes sense since rotated pointing straight down or up, the nodal point is always going to be the distance of the rotation out in front or back. And, of course, the longest point forward has to be the length of the hypotenuse as you rotate around 360° you are just subscribing a circle with the nodal point.
Of course, this is somewhat esoteric depending on the setup and what you are shooting.